Given two strings s and t, return true if they are equal when both are typed into empty text editors. ‘#’ means a backspace character. Note that after backspacing an empty text, the text will continue empty.
Example 1: Input: s = “ab#c”, t = “ad#c” Output: true Explanation: Both s and t become “ac”. Example 2: Input: s = “ab##”, t = “c#d#” Output: true Explanation: Both s and t become “”. Example 3: Input: s = “a#c”, t = “b” Output: false Explanation: s becomes “c” while t becomes “b”.
1 <= s.length, t.length <= 200 s and t only contain lowercase letters and '#' characters.
class Solution: def backspaceCompare(self, s: str, t: str) -> bool: def build(s): stack =  for c in s: if c != "#": stack.append(c) elif stack: stack.pop() return "".join(stack) return build(s) == build(t)
class Solution(object): def backspaceCompare(self, S, T): def F(S): skip = 0 for x in reversed(S): if x == '#': skip += 1 elif skip: skip -= 1 else: yield x return all(x == y for x, y in itertools.zip_longest(F(S), F(T)))