71. Simplify Path

Simplify Path - LeetCode

Given a string path, which is an absolute path (starting with a slash ‘/') to a file or directory in a Unix-style file system, convert it to the simplified canonical path. In a Unix-style file system, a period ‘.’ refers to the current directory, a double period ‘..’ refers to the directory up a level, and any multiple consecutive slashes (i.e. ‘//') are treated as a single slash ‘/’. For this problem, any other format of periods such as ‘…’ are treated as file/directory names. The canonical path should have the following format:

The path starts with a single slash '/'.
Any two directories are separated by a single slash '/'.
The path does not end with a trailing '/'.
The path only contains the directories on the path from the root directory to the target file or directory (i.e., no period '.' or double period '..')Return __the simplified canonical path__.

Example 1: Input: path = “/home/” Output: “/home” Explanation: Note that there is no trailing slash after the last directory name. Example 2: Input: path = “/../” Output: “/” Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go. Example 3: Input: path = “/home//foo/” Output: “/home/foo” Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.


1 <= path.length <= 3000
path consists of English letters, digits, period '.', slash '/' or '_'.
path is a valid absolute Unix path.

  • code
class Solution:
    def simplifyPath(self, path: str) -> str:
        path_list = path.split('/')
        rs = []
        for p in path_list:
            if p == '..':
                if rs:
            elif p == '.':
            elif p:
        return '/' + '/'.join(rs)