# 71. Simplify Path

Simplify Path - LeetCode

Given a string path, which is an absolute path (starting with a slash ‘/') to a file or directory in a Unix-style file system, convert it to the simplified canonical path. In a Unix-style file system, a period ‘.’ refers to the current directory, a double period ‘..’ refers to the directory up a level, and any multiple consecutive slashes (i.e. ‘//') are treated as a single slash ‘/’. For this problem, any other format of periods such as ‘…’ are treated as file/directory names. The canonical path should have the following format:

``````The path starts with a single slash '/'.
Any two directories are separated by a single slash '/'.
The path does not end with a trailing '/'.
The path only contains the directories on the path from the root directory to the target file or directory (i.e., no period '.' or double period '..')Return __the simplified canonical path__.
``````

Example 1: Input: path = “/home/” Output: “/home” Explanation: Note that there is no trailing slash after the last directory name. Example 2: Input: path = “/../” Output: “/” Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go. Example 3: Input: path = “/home//foo/” Output: “/home/foo” Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.

Constraints:

``````1 <= path.length <= 3000
path consists of English letters, digits, period '.', slash '/' or '_'.
path is a valid absolute Unix path.
``````

• code
``````class Solution:
def simplifyPath(self, path: str) -> str:
path.replace('//','/')
path_list = path.split('/')
rs = []
for p in path_list:
if p == '..':
if rs:
rs.pop()
elif p == '.':
continue
elif p:
rs.append(p)
return '/' + '/'.join(rs)
``````