42. Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining.

Example 1: Input: height = [0,1,0,2,1,0,1,3,2,1,2,1] Output: 6 Explanation: The above elevation map (black section) is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Example 2: Input: height = [4,2,0,3,2,5] Output: 9

Constraints:

n == height.length 	
1 <= n <= 2 * 104 	
0 <= height[i] <= 105

  • code
class Solution {
    public int trap(int[] height) {
        int left = 0, right = height.length - 1;
        int leftMax = 0, rightMax = 0;
        int res = 0;
        while (left < right){
            if (height[left] > leftMax) leftMax = height[left];
            if (height[right] > rightMax) rightMax = height[right];
            if (leftMax < rightMax){
                res += leftMax - height[left];
                left++;
            }else{
                res += rightMax - height[right];
                right--; 
            }
        }
        return res;
    }
}