1295. Find Numbers with Even Number of Digits

array

Given an array nums of integers, return how many of them contain an even number of digits. Example 1: Input: nums = [12,345,2,6,7896] Output: 2 Explanation: 12 contains 2 digits (even number of digits). 345 contains 3 digits (odd number of digits). 2 contains 1 digit (odd number of digits). 6 contains 1 digit (odd number of digits). 7896 contains 4 digits (even number of digits). Therefore only 12 and 7896 contain an even number of digits.

  • code
class Solution:
    def findNumbers(self, nums: List[int]) -> int:
        count = 0
        for v in nums:
            if len(str(v)) % 2 == 0:
                count += 1
        return count
  • code
class Solution:
    def findNumbers(self, nums: List[int]) -> int:
        return len([x for x in nums if len(str(x)) % 2 == 0])