11. Container With Most Water

Container With Most Water - LeetCode

You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]). Find two lines that together with the x-axis form a container, such that the container contains the most water. Return the maximum amount of water a container can store. Notice that you may not slant the container.

Example 1: Input: height = [1,8,6,2,5,4,8,3,7] Output: 49 Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49. Example 2: Input: height = [1,1] Output: 1

Constraints:

n == height.length
2 <= n <= 105
0 <= height[i] <= 104

  • code
class Solution {
    public int maxArea(int[] height) {
        int l = 0, r = height.length - 1;
        int area = 0, res = 0;
        while (l < r){
            area = (r - l) * Math.min(height[l], height[r]);
            res = Math.max(area, res);
            if (height[l] <= height[r]){
                l++;
            }else{
                r--;
            }
        }

        return res;
    }
}
  • code
class Solution:
    def maxArea(self, height: List[int]) -> int:
        left, right = 0, len(height) - 1
        res = 0
        while left < right:
            res = max(res, (right - left ) * min(height[left], height[right]))
            if height[left] < height[right]:
                left += 1
            else:
                right -= 1
                
        return res