# 11. Container With Most Water

Container With Most Water - LeetCode

You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]). Find two lines that together with the x-axis form a container, such that the container contains the most water. Return the maximum amount of water a container can store. Notice that you may not slant the container.

Example 1: Input: height = [1,8,6,2,5,4,8,3,7] Output: 49 Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49. Example 2: Input: height = [1,1] Output: 1

Constraints:

``````n == height.length
2 <= n <= 105
0 <= height[i] <= 104
``````

• code
``````class Solution {
public int maxArea(int[] height) {
int l = 0, r = height.length - 1;
int area = 0, res = 0;
while (l < r){
area = (r - l) * Math.min(height[l], height[r]);
res = Math.max(area, res);
if (height[l] <= height[r]){
l++;
}else{
r--;
}
}

return res;
}
}
``````
• code
``````class Solution:
def maxArea(self, height: List[int]) -> int:
left, right = 0, len(height) - 1
res = 0
while left < right:
res = max(res, (right - left ) * min(height[left], height[right]))
if height[left] < height[right]:
left += 1
else:
right -= 1

return res
``````