Maximum Depth of Binary Tree - LeetCode
Given the root of a binary tree, return its maximum depth. A binary tree’s maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1: Input: root = [3,9,20,null,null,15,7] Output: 3 Example 2: Input: root = [1,null,2] Output: 2
Constraints:
The number of nodes in the tree is in the range [0, 104].
-100 <= Node.val <= 100
- code
class Solution:
def maxDepth(self, root: TreeNode) -> int:
if not root:
return 0
return 1 + max(self.maxDepth(root.left), self.maxDepth(root.right))
- c iteration
class Solution:
def maxDepth(self, root):
if not root: return 0
level = [root]; depth = 0
while level:
depth += 1
level = [i for n in level for i in (n.left, n.right) if i]
return depth
- code stack iteration
class Solution:
def maxDepth(self, root):
stack = []
if root:
stack.append((1, root))
depth = 0
while stack:
current_depth, root = stack.pop()
if root:
depth = max(depth, current_depth)
stack.append((current_depth + 1, root.left))
stack.append((current_depth + 1, root.right))
return depth